A resistor develops 400 J of thermal energy in 10 s when a current of 2 A is passed through it.
Text Solution
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CHECK THE SOLUTION.
[ 10 Ω Ω , 3200 J]
Sol. H = I 2 R
t
⇒ 400 = 2 2 × R × 10
⇒ R = 10 Ω Ω
H = I 2 R
t
Now I = 4A,
t = 20s
⇒ H = 4 2 × 10 × 20 = 3200 J
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